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Best673518
@Best673518
October 2021
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Сократите дробь: (задания:ж,з,и)
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mmb1
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(a²-3a)/(a²+3a-18)=a(a-3)/(a-3)(a+6)=a/(a+6)
d=9+72=81
a12=(-3+-9)/2=-6 3
(4x²-8x+3)/(4x²-1)=(2x-1)(2x-3)/(2x-1)(2x+1)=(2x-3)/(2x+1)
в=64-48=16
х12=(8+-4)/8=1/2 3/2
(m²+4m-5)/(m²+7m+10)=(m+5)(m-1)/(m+5)(m+2)=(m-1)/(m+2)
d1=16+20=36
m12=(-4+-6)/2=-5 1
d2=49-40=9
m12=(-7+-3)/2=-5 -2
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Answers & Comments
Verified answer
(a²-3a)/(a²+3a-18)=a(a-3)/(a-3)(a+6)=a/(a+6)d=9+72=81
a12=(-3+-9)/2=-6 3
(4x²-8x+3)/(4x²-1)=(2x-1)(2x-3)/(2x-1)(2x+1)=(2x-3)/(2x+1)
в=64-48=16
х12=(8+-4)/8=1/2 3/2
(m²+4m-5)/(m²+7m+10)=(m+5)(m-1)/(m+5)(m+2)=(m-1)/(m+2)
d1=16+20=36
m12=(-4+-6)/2=-5 1
d2=49-40=9
m12=(-7+-3)/2=-5 -2