Сократите дробь
(5x^2-3x-2)/(5x^2+2x)= (5*(x-1)*(x+0,4))/(x(5x+2)) = ((x-1)*(5x+2))/(x(5x+2)) = (x-1)/x
5x²-3x-2 (5x+2)(x-1) x-1
----------- = ----------------- = -------
5x²+2x x(5x+2) x
5x²-3x-2
Δ=9-4*5*(-2)=49
√Δ=7
x1=(3-7)/10=-2/5
x2=1
5(x+2/5)(x-1)=(5x+2)(x-1)
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Answers & Comments
(5x^2-3x-2)/(5x^2+2x)= (5*(x-1)*(x+0,4))/(x(5x+2)) = ((x-1)*(5x+2))/(x(5x+2)) = (x-1)/x
5x²-3x-2 (5x+2)(x-1) x-1
----------- = ----------------- = -------
5x²+2x x(5x+2) x
5x²-3x-2
Δ=9-4*5*(-2)=49
√Δ=7
x1=(3-7)/10=-2/5
x2=1
5(x+2/5)(x-1)=(5x+2)(x-1)