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caketea
@caketea
July 2022
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solve this ..................
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Newtion
Verified answer
1.
Proof:
Let
be a given polynomial function.
Then, by
Polynomial remainder theorem,
is a divisor (factor) of
if and only if
.
Hence,
Q.E.D.
2.
Since
is a divisor of
, there is exists
such that
.
Hence,
.
Therefore,
Now, let's find the roots of g(x):
Hence,
are solutions of f(x).
1 votes
Thanks 0
caketea
WTF! i didn't understand a thing
Newtion
You asked to solve it, i solved it. I don't know, what you don't understand...
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Answers & Comments
Verified answer
1.Proof:
Let be a given polynomial function.
Then, by Polynomial remainder theorem, is a divisor (factor) of if and only if .
Hence,
Q.E.D.
2.
Since is a divisor of , there is exists such that .
Hence,
.
Therefore,
Now, let's find the roots of g(x):
Hence,
are solutions of f(x).