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danyamotin03
@danyamotin03
October 2021
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сосчитайте и получите ответ в двоичных восьмеричных и десятичных системах исчисления: 1111001(2сс)+7(8)+12(10)
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petyaGavrikov
Verified answer
1111001(2) = 2^6+2^5+2^4+2^3+1 = 64+32+16+8+1 = 121(10)
7(8) = 7(10)
121+7+12 = 140(10)
140(10) = 128+8+4 = 2^7+2^3+2^2 = 10001100(2)
140(10) = 2*64+8+4 = 2*8^2+1*8^1+4*8^0 = 214(8)
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Answers & Comments
Verified answer
1111001(2) = 2^6+2^5+2^4+2^3+1 = 64+32+16+8+1 = 121(10)7(8) = 7(10)
121+7+12 = 140(10)
140(10) = 128+8+4 = 2^7+2^3+2^2 = 10001100(2)
140(10) = 2*64+8+4 = 2*8^2+1*8^1+4*8^0 = 214(8)