ax²+px+q=0
a=1
x²+px+q=0
x1+x2=-p
x1*x2=q
-1+(-12)= -13
-1*(-12)= 12
p=13
q=12
Ответ: x²+13x+12=0
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Verified answer
ax²+px+q=0
a=1
x²+px+q=0
x1+x2=-p
x1*x2=q
-1+(-12)= -13
-1*(-12)= 12
p=13
q=12
Ответ: x²+13x+12=0