Составь квадратное уравнение с помощью заданных корней: 11 и –3.
x2 – 8x + 33 = 0
x2 + 8x – 33 = 0
x2 – 8x – 33 = 0
x2 – 8x + 33 = 0
x2 + 8x – 33 = 0
x2 – 8x – 33 = 0
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
x²-8x-33=0
Объяснение:
(x-11)(x-(-3)=(x-11)(x+3)=x²+3x-11x-33=x²-8x-33
По теореме Виета:
-3+11=-b
-b=8 |•(-1)
b=-8
-3×11=c
c=-33
x²-8x-33