2СrO3 + 2NH3 = Cr2O3 + N2 + 3H2O
Сr(+6)O(-2) + N(-3)H(+) = Cr(+3)O(-2) + N(0) + H(+)O(-2)
Cr(+6) +3e -> Cr(+3) 2 в-ие
ок-ль
N(-3) -3e -> N(0) 2 ок-ие
в-ль
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Verified answer
2СrO3 + 2NH3 = Cr2O3 + N2 + 3H2O
Сr(+6)O(-2) + N(-3)H(+) = Cr(+3)O(-2) + N(0) + H(+)O(-2)
Cr(+6) +3e -> Cr(+3) 2 в-ие
ок-ль
N(-3) -3e -> N(0) 2 ок-ие
в-ль