Ответ:
#include<iostream>
#include<math.h>
int main()
{
double f,x;
for(x=1; x<=4.2; x+=0.2)
f=((pow(M_E,2*x)-pow(M_E,-x))*sin(log(fabs(x))));
std::cout << "F("<<x<<") = "<< f<<"\n";
}
return 0;
Объяснение:
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Answers & Comments
Ответ:
#include<iostream>
#include<math.h>
int main()
{
double f,x;
for(x=1; x<=4.2; x+=0.2)
{
f=((pow(M_E,2*x)-pow(M_E,-x))*sin(log(fabs(x))));
std::cout << "F("<<x<<") = "<< f<<"\n";
}
return 0;
}
Объяснение: