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prorok133751
@prorok133751
August 2022
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составить уравнение реакции взаимодействия алюминия с хлором серой кислородом азотом фосфором
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svetka1574
Verified answer
2Al+3Cl2=2AlCl3
2Al+3S=Al2S3
4Al+3O2=2Al2O3
2Al+N2=2AlN
Al+P=AlP
2 votes
Thanks 2
khursandov
Al вступает в реакцию с красным фосфором P4
khursandov
2Al + 3Cl2 = 2AlCl3
2Al + 3S = Al2S3
4Al + 3O2 = 2Al2O3
2Al + N2 = 2AlN
4Al + P4 = 4AlP
2 votes
Thanks 2
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Answers & Comments
Verified answer
2Al+3Cl2=2AlCl32Al+3S=Al2S3
4Al+3O2=2Al2O3
2Al+N2=2AlN
Al+P=AlP
2Al + 3S = Al2S3
4Al + 3O2 = 2Al2O3
2Al + N2 = 2AlN
4Al + P4 = 4AlP