Ответ:
y = 8 1/3 при x = 1/3
Объяснение:
y = 8 + 2·x – 3·x² = –3·(x² – 2/3·x) + 8 =
= –3·(x² – 2·(1/3)·x + (1/3)² – (1/3)²) + 8 =
= –3·(x² – 2·(1/3)·x + (1/3)²) + 3·(1/3)² + 8 =
= –3·(x – 1/3)² + 3·1/9 + 8 = –3·(x – 1/3)² + 1/3 + 8 =
= –3·(x – 1/3)² + 8 1/3 ≤ 8 1/3.
Тогда функция y = 8 + 2·x – 3·x² принимает наибольшее значение 8 1/3 при x = 1/3.
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Ответ:
y = 8 1/3 при x = 1/3
Объяснение:
y = 8 + 2·x – 3·x² = –3·(x² – 2/3·x) + 8 =
= –3·(x² – 2·(1/3)·x + (1/3)² – (1/3)²) + 8 =
= –3·(x² – 2·(1/3)·x + (1/3)²) + 3·(1/3)² + 8 =
= –3·(x – 1/3)² + 3·1/9 + 8 = –3·(x – 1/3)² + 1/3 + 8 =
= –3·(x – 1/3)² + 8 1/3 ≤ 8 1/3.
Тогда функция y = 8 + 2·x – 3·x² принимает наибольшее значение 8 1/3 при x = 1/3.