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efimchernov001
@efimchernov001
August 2022
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Составьте квадратное уравнение корни которого равны 7-√5. И 7-√5
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zinaidazina
x₁ = x₂ = 7-√5
(x- x₁)(x - x₂) = 0
(x- (7-√5))² = 0
x² - 2·x·(7-√5) + (7-√5)² = 0
x² - (14-2√5)x + 49 - 2·7·√5 + 5 = 0
x² - (14-2√5)x + 54 - 14√5 = 0
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Answers & Comments
x₁ = x₂ = 7-√5
(x- x₁)(x - x₂) = 0
(x- (7-√5))² = 0
x² - 2·x·(7-√5) + (7-√5)² = 0
x² - (14-2√5)x + 49 - 2·7·√5 + 5 = 0
x² - (14-2√5)x + 54 - 14√5 = 0