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coolpetrov
@coolpetrov
August 2021
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Составьте молекулярные и ионные уравнения реакции взаимодействия следующих веществ:
Cr2O3+H2SO4----->
MgOHCl+HCl---->
Ca(OH)2+H2SO4--->
NaCN+HNO3--->
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mrvladimir2
Verified answer
Cr2O3 + 3H2SO4 = Cr2(SO4)3 + 3H2O
Cr₂O₃+6H⁺+3SO₄²⁻ = 2Cr²⁺+3SO₄²⁻+3H₂O
Cr₂O₃+6H⁺ = 2Cr₂⁺+3H₂O
MgOHCl + HCl = MgCl₂+H₂O
Mg²⁺+OH⁻+Cl⁻+H⁺+Cl⁻=Mg²⁺+2Cl⁻+H₂O
H⁺+OH⁻=H₂O
Ca(OH)2+H2SO4 = CaSO4 + 2H2O
Ca²⁺+2OH⁻+2H⁺+SO₄²⁻=Ca²⁺+SO₄²⁻+2H₂O
2H⁺+2OH⁻=2H₂O
NaCN + HNO₃≠ нет связывающих ионов
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Answers & Comments
Verified answer
Cr2O3 + 3H2SO4 = Cr2(SO4)3 + 3H2OCr₂O₃+6H⁺+3SO₄²⁻ = 2Cr²⁺+3SO₄²⁻+3H₂O
Cr₂O₃+6H⁺ = 2Cr₂⁺+3H₂O
MgOHCl + HCl = MgCl₂+H₂O
Mg²⁺+OH⁻+Cl⁻+H⁺+Cl⁻=Mg²⁺+2Cl⁻+H₂O
H⁺+OH⁻=H₂O
Ca(OH)2+H2SO4 = CaSO4 + 2H2O
Ca²⁺+2OH⁻+2H⁺+SO₄²⁻=Ca²⁺+SO₄²⁻+2H₂O
2H⁺+2OH⁻=2H₂O
NaCN + HNO₃≠ нет связывающих ионов