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Beautiful00
@Beautiful00
August 2022
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Составьте программу квадратного уравнение и блок схему 0,5х2+2х-4=0 в паскале
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danabel2000
Var d,x1,x2:real;
begin
d:=sqr(2)-4*0.5*(-4);
x1:=(-2+sqrt(d))/(2*0.5);
x2:=(-2-sqrt(d))/(2*0.5);
writeln('x1=',x1:3:1,' x2=',x2:3:1);
end.
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Answers & Comments
begin
d:=sqr(2)-4*0.5*(-4);
x1:=(-2+sqrt(d))/(2*0.5);
x2:=(-2-sqrt(d))/(2*0.5);
writeln('x1=',x1:3:1,' x2=',x2:3:1);
end.