Составьте уравнение окружности с центром в точке (-3;2) и проходящей через точку (1:5)
r^2 = (1+3)^2+(5-2)^2
r^2 =16+9=25
r=5
(x+3)^2+(y-2)^2 = 25
(x-x_s)²+(y-y_s)=r²
r²=(1-(-3))²+(5-2)²
r²=16+9
r²=25
(x+3)²+(y-2)²=25
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Verified answer
r^2 = (1+3)^2+(5-2)^2
r^2 =16+9=25
r=5
(x+3)^2+(y-2)^2 = 25
Verified answer
(x-x_s)²+(y-y_s)=r²
r²=(1-(-3))²+(5-2)²
r²=16+9
r²=25
(x+3)²+(y-2)²=25