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victoriareih
@victoriareih
October 2021
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Составьте уравнение в ионно-молекулярном виде BaCl2+K3PO4.
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Feynman
3BaCl2 + 2K3PO4 = 6KCl + Ba3(PO4)2↓
3Ba(2+) + 6Cl(-) + 6K(+) + 2PO4(2-) = 6K(+) + 6Cl(-) + Ba3(PO4)2↓
Сокрщ.:
3Ba(2+) + 2PO4(2-) = Ba3(PO4)2↓
4 votes
Thanks 4
victoriareih
Спасибо большое!!!!!!!!!!
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Answers & Comments
3Ba(2+) + 6Cl(-) + 6K(+) + 2PO4(2-) = 6K(+) + 6Cl(-) + Ba3(PO4)2↓
Сокрщ.:
3Ba(2+) + 2PO4(2-) = Ba3(PO4)2↓