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OloloshaOloloeva
@OloloshaOloloeva
July 2022
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Составьте уравнения реакций,происходящих при снятии налета ржавчины(смеси Fe2O3 и Fe(OH)3) с поверхности соляной кислоты.
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mikhailkalinin
1)Mg_2HCl=MgCl2+H2
Mg+2H+2Cl=Mg+2C+H2
Mg+2H=Mg+H2
2)n(H2)=5.6:22.4=0.25моль=n(Mg)
Mg+2HCl=MgCl2+H2
1-------------------------1
m(Mg)=24*0.25=6г
3) 2Na+2H2O=2NaOH+H2
CuSO4+2NaOH=Cu(OH)2+Na2SO4
4)100*4.9=49г H2SO4
n(H2SO4)=49:98=0.5 моль=n(H2)
H2SO4+Zn=ZnSO4+H2
1-----------------------------1
V=22.4*0.5=11.2л
5) натрий, калий франций
0 votes
Thanks 1
Alhimica
Fe2O3+6HCl=2FeCl3+3H2O
Fe(OH)3+3HCl = FeCl3+3H2O
2 votes
Thanks 1
OloloshaOloloeva
Спасибо большое)
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Answers & Comments
Mg+2H+2Cl=Mg+2C+H2
Mg+2H=Mg+H2
2)n(H2)=5.6:22.4=0.25моль=n(Mg)
Mg+2HCl=MgCl2+H2
1-------------------------1
m(Mg)=24*0.25=6г
3) 2Na+2H2O=2NaOH+H2
CuSO4+2NaOH=Cu(OH)2+Na2SO4
4)100*4.9=49г H2SO4
n(H2SO4)=49:98=0.5 моль=n(H2)
H2SO4+Zn=ZnSO4+H2
1-----------------------------1
V=22.4*0.5=11.2л
5) натрий, калий франций
Fe(OH)3+3HCl = FeCl3+3H2O