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bladex2017
@bladex2017
August 2022
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Срочно! 1 задачка! За ранее очень признателен!
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Ответ:
DB3=
Пошаговое объяснение:
DB3=
DD3=
D3B3=
DB3=
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Answers & Comments
Ответ:
DB3=![\sqrt{10} \sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7B10%7D)
Пошаговое объяснение:
DB3=![\sqrt{DD3^{2} +D3B3^{2} } \sqrt{DD3^{2} +D3B3^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7BDD3%5E%7B2%7D%20%2BD3B3%5E%7B2%7D%20%7D)
DD3=![\sqrt{(2DD1)^{2} +D1D2^{2} }=\sqrt{2^{2}+1^{2} }=\sqrt{5} \sqrt{(2DD1)^{2} +D1D2^{2} }=\sqrt{2^{2}+1^{2} }=\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B%282DD1%29%5E%7B2%7D%20%2BD1D2%5E%7B2%7D%20%7D%3D%5Csqrt%7B2%5E%7B2%7D%2B1%5E%7B2%7D%20%7D%3D%5Csqrt%7B5%7D)
D3B3=![\sqrt{A3D3^{2} +A3B3^{2} }=\sqrt{2^{2} +1^{2} }=\sqrt{5} \sqrt{A3D3^{2} +A3B3^{2} }=\sqrt{2^{2} +1^{2} }=\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7BA3D3%5E%7B2%7D%20%2BA3B3%5E%7B2%7D%20%7D%3D%5Csqrt%7B2%5E%7B2%7D%20%2B1%5E%7B2%7D%20%7D%3D%5Csqrt%7B5%7D)
DB3=![\sqrt{DD3^{2} +D3B3^{2} }=\sqrt{5+5} =\sqrt{10} \sqrt{DD3^{2} +D3B3^{2} }=\sqrt{5+5} =\sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7BDD3%5E%7B2%7D%20%2BD3B3%5E%7B2%7D%20%7D%3D%5Csqrt%7B5%2B5%7D%20%3D%5Csqrt%7B10%7D)