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aqua3
@aqua3
July 2022
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СРОЧНО 10 баллов помогите решить 5
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oganesbagoyan
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5. * * * формулы приведения * * *
sin(π/2+α) /sin(3π/2+α) +cos(3π+α)/ ( cos(π/2+α) -1 ) =
cosα) /(-cosα) +(- cosα / ( -cosα -1 ) = - 1 +cosα / (cosα +1 ) =
( - cosα -1 +cosα ) /(cosα +1) = -1 /(cosα +1) .
* * * cos(3π+α) = cos(2π+ (π+α) )= cos(π+α) = - cosα * * *
а если
sin(π/2+α) / sin(3π/2+α) +cos(3π+α) / cos(π/2+α) -1 =
cosα) /(-cosα) +(-cosα / ( -cosα) -1 = - 1 +1 - 1 = -1.
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5. * * * формулы приведения * * *sin(π/2+α) /sin(3π/2+α) +cos(3π+α)/ ( cos(π/2+α) -1 ) =
cosα) /(-cosα) +(- cosα / ( -cosα -1 ) = - 1 +cosα / (cosα +1 ) =
( - cosα -1 +cosα ) /(cosα +1) = -1 /(cosα +1) .
* * * cos(3π+α) = cos(2π+ (π+α) )= cos(π+α) = - cosα * * *
а если sin(π/2+α) / sin(3π/2+α) +cos(3π+α) / cos(π/2+α) -1 =
cosα) /(-cosα) +(-cosα / ( -cosα) -1 = - 1 +1 - 1 = -1.