5)А
=1/2[cos(x+x/2) +cos(x-x/2)]-1/2[cos(x-x/2)-cos(x+x/2]
=1/2[cos(x+x/2) +cos(x-x/2)-cos(x-x/2)+cos(x+x/2)]
=1/2[2cos(x+x/2)]
=cos 3x/2
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Answers & Comments
2. 0.75π=3/4*180=135°
3. sin2*π/2= sinπ=0
4. это формула тангенса суммы
дробь равна tg(76+44)=tg120°=-tg60°= -√3
5. формула косинуса суммы
=cos(x+x/2)=cos (3x/2)
5)А
=1/2[cos(x+x/2) +cos(x-x/2)]-1/2[cos(x-x/2)-cos(x+x/2]
=1/2[cos(x+x/2) +cos(x-x/2)-cos(x-x/2)+cos(x+x/2)]
=1/2[2cos(x+x/2)]
=cos 3x/2