d) (√3+2√2-√3-2√2)²=(√(1+√2)²-√3-2√2)²=(√(1+√2)²-(√(1-√2)²)²=(1+√2-√(1-√2)²)²=(1+√2-(√2-1))²=(1+√2-√2+1)²=(1+1)²=2²=4
b)√60+(√5-√3)²=2√15+(√5-√3)²=2√15+5-2√15+3=5+3=8
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d) (√3+2√2-√3-2√2)²=(√(1+√2)²-√3-2√2)²=(√(1+√2)²-(√(1-√2)²)²=(1+√2-√(1-√2)²)²=(1+√2-(√2-1))²=(1+√2-√2+1)²=(1+1)²=2²=4
b)√60+(√5-√3)²=2√15+(√5-√3)²=2√15+5-2√15+3=5+3=8