Ответ:
1) Відносна молекулярна маса Mr(C2H4O2)=24+4+32=60
w(C)= 24:60=40%
w(H)= 4:60=7%
w(O)=32:60=53%
2)Mr(C6H12O6)=72+12+96=180
w(C)=72:180=40%
w(H)=12:180=7%
w(O)=96:180=53%
3)Mr(C12H22O11)=144+22+176=342
w(C)=144:342=42%
w(H)=22:342=0,6%
w(O)=176:342=51%
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Answers & Comments
Ответ:
1) Відносна молекулярна маса Mr(C2H4O2)=24+4+32=60
w(C)= 24:60=40%
w(H)= 4:60=7%
w(O)=32:60=53%
2)Mr(C6H12O6)=72+12+96=180
w(C)=72:180=40%
w(H)=12:180=7%
w(O)=96:180=53%
3)Mr(C12H22O11)=144+22+176=342
w(C)=144:342=42%
w(H)=22:342=0,6%
w(O)=176:342=51%