1) x² - 3x - 4 >= 0
x² - 4x + x - 4 >= 0
(x+1)(x-4) >= 0
x ∈ (-∞ ; -1] ∪ [4 ; +∞)
2) - x² - 2x + 48 < 0
x² + 2x - 48 > 0
(x+8)(x-6) > 0
x ∈ (-∞ ; -8) ∪ (6 ; +∞)
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Answers & Comments
1) x² - 3x - 4 >= 0
x² - 4x + x - 4 >= 0
(x+1)(x-4) >= 0
x ∈ (-∞ ; -1] ∪ [4 ; +∞)
2) - x² - 2x + 48 < 0
x² + 2x - 48 > 0
(x+8)(x-6) > 0
x ∈ (-∞ ; -8) ∪ (6 ; +∞)