Ответ:
Объяснение:
sinA = BC/AB
= 5/AB
AB= 5*2 / = 10/
tgA = BC/AC
= 5/ AC
AC= 5/
∠B= 90-∠A = 90-60= 30°
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Ответ:
Объяснение:
sinA = BC/AB
AB= 5*2 /
= 10/
tgA = BC/AC
AC= 5/![\sqrt{3} \sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
∠B= 90-∠A = 90-60= 30°