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temerlan2020
@temerlan2020
July 2022
1
10
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СРОЧНО!!!!!!!!!!!!!! ДАЮ 20 БАЛОВ
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LosKxDD
4 вариант
1) а)
б)
2)
3)
4)
5)
6)
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Answers & Comments
4 вариант
1) а)
б)
2)
3)
4)
5)
6)