Срочно!! Даю 30 баллов. Created by alinazaporozhets976. algebra-ru

Срочно!! Даю 30 баллов...

NNNLLL54

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Ответ:

$3)\ \ \dfrac{cos^22a}{sin4a}=\dfrac{cos^22a}{2\cdot sin2a\cdot cos2a}=\dfrac{cos2a}{2\cdot sina}=\dfrac{1}{2}\, ctg2a\\\\\\4)\ \ \dfrac{(sina+cosa)^2}{1-sin^22a}=\dfrac{sin^2a+2\, sina\cdot cosa+cos^2a}{1-sin^22a}=\dfrac{1+sin2a}{(1-sin2a)(1+sin2a)}=\\\\=\dfrac{1}{1-sin2a}\\\\\\3)\ \ ctga=\dfrac{cosa}{sina}$

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kenzegulzuparbaeva

Ответ:

1)cos²2d/sin4d=cos²2d/2sin2d•cos2d=>упростим cos²2d сcos2d= из этого =>сos2d/2sin2d

2)ctgd=cosd/sind

3)(sind+cosd)²/1-sin²d=sin²d+2sindcosd+cos²d/1-sin²2d=1+2sindcosd/1-sin²2d=1+sin2d/1-sin²2d

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Answers & Comments

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srochno 5primer pozhalujsta

napishi pismo geroyu skazki po predlozhennomu nachalu nachalo zdravstvuj myshonok p

izobrazite na koordinatnoj ploskosti mnozhestvo tochek zadannoe neravenstvom h

reshite sistemu uravnenij hu 1 hu1

5p rebyatochen srochnoproshu vas

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