(9)
AD = sqrt(6^2-4,8^2) = sqrt(36-23,04)=sqrt12,96 =3,6
6=sqrt(AB*3,6); 36=AB*3,6; AB=36/3,6=10
BD=10-3,6=6,4
BC=sqrt(100-36)=sqrt64=8
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(9)
AD = sqrt(6^2-4,8^2) = sqrt(36-23,04)=sqrt12,96 =3,6
6=sqrt(AB*3,6); 36=AB*3,6; AB=36/3,6=10
BD=10-3,6=6,4
BC=sqrt(100-36)=sqrt64=8
CD = sqrt(AD*DB)=sqrt(2*18) =6(м)
ADC по теореме Пифагора:
AC =sqrt(CD^2 + AD^2) = sqrt(6^2+2^2) =2 sqrt10
BDC по теореме Пифагора:
BC =sqrt(CD^2 + BD^2) = sqrt(6^2+18^2)=6 sqrt10