СРОЧНО!!! ДАЮ 50Б!!!. Created by alice4049. algebra-ru

СРОЧНО!!! ДАЮ 50Б!!!...

alice4049 @alice4049

July 2022 1 3 Report

СРОЧНО!!! ДАЮ 50Б!!!

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NNNLLL54

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$\displaystyle 1)\ \ \ \frac{x+4}{4x^2-13x+3}\\\\\\ODZ:\ \ 4x^2-13x+3\ne 0\ \ ,\ \ x_1\ne 0,25\ \ ,\ \ x_2\ne 3\\\\x\in D(y)\ \ ,\ \ D(y)=(-\infty \, ;\ 0,25\ )\cup (\ 0,25\ ;\ 3\ )\cup (\ 3\ ;+\infty \, )$

$\displaystyle 2)\ \ \frac{a^{21}}{a^{11}\cdot a^{12}}=a^{21-11-12}=a^{-2}=\frac{1}{a^2}=\frac{1}{(0,2)^2}=\frac{1}{\Big(\dfrac{1}{5}\Big)^2}=25$

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molekula binarnogo soedineniya soderzhit 18 elektronov iz kotoryh 10 uchastvuyut v

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alice4049 July 2022 | 0 Ответы

skolko mol atomov n soderzhitsya v 2 mol molekuly n2

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b507feae669c95e22b3b17334ad6c442

a9d4a755b50ab41276ddcc95eb853618

8 63c98b4fd6209

e7dfc91c56b7a9db662bae7a57caf91b

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100 10 25

c co2 h2co3caco3co2k2co3

s polnym resheniem bez resheniya srazu blokiruyu

molekula binarnogo soedineniya soderzhit 18 elektronov iz kotoryh 10 uchastvuyut v

skolko mol atomov n soderzhitsya v 2 mol molekuly n2

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