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Ответ:

Объяснение:

CH4+CL2 ->(hV) CH3Cl+HCL

2CH3CL+2Na-> C2H6+2NaCl

C2H6+Cl2 ->(hV) C2H5Cl+HCL

2C2H5Cl+2Na->C4H10+2NaCl

2C4H10+13O2-> 8CO2+10H20+Q (Горение)

CaC2+2H2O-> C2H2+Ca(OH)2

C2H2+H2->C2H4

nCH2=CH2 -> [-CH2-CH2-]n