Ответ:
M(Al(OH)3) = 27 + (16+1)*3) = 78 g/mol
W(Al) = 27 / 78 * 100% = 34.61%
W(O) = 16*3 / 78 *100%=61.54%
W(H) = 1*3 / 78*100% = 3.85%
Объяснение:
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
M(Al(OH)3) = 27 + (16+1)*3) = 78 g/mol
W(Al) = 27 / 78 * 100% = 34.61%
W(O) = 16*3 / 78 *100%=61.54%
W(H) = 1*3 / 78*100% = 3.85%
Объяснение: