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nyuraannashev
@nyuraannashev
August 2021
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СРОЧНО ХИМИЯ!!!!!!!!!!!какой объем азота может прореагировать с 10 л водорода
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Alexei78
Дано
V(H2) = 10 L
------------------------
v(N2)-?
N2+3H2-->2NH3
Xл(N2) / 1mol = 10л(H2) / 3mol
X = 1*10 / 3 = 3.33 L
ответ 3.33 л
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Answers & Comments
V(H2) = 10 L
------------------------
v(N2)-?
N2+3H2-->2NH3
Xл(N2) / 1mol = 10л(H2) / 3mol
X = 1*10 / 3 = 3.33 L
ответ 3.33 л