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Lucyena
@Lucyena
August 2022
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Срочно!
Какова S прямоугольника?
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gulsaya0399
CD=1/2AC=4
AD^2=AC^2-CD^2=64-16=48
AD=4 корень3
S=AD*CD=4 корень3 *4=16 корень 3
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Lucyena
По теореме же AC^2 + CD^2 , не?
gulsaya0399
тут мы должны найти катет АД,поэтому AD^2=AC^2-CD^2
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Answers & Comments
AD^2=AC^2-CD^2=64-16=48
AD=4 корень3
S=AD*CD=4 корень3 *4=16 корень 3