Ответ:
(3b+1)^2-(b-7)^2=(3b+1-(b-7))•(3b+1+(b-7))=(3b+1-b+7)•(3b+1+b-7)=(2b+8)•(4b-6)=2(b+4)•2(2b-3)=2•2(b+4)•(2b-3)=4(b+4)•(2b-3)
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Ответ:
(3b+1)^2-(b-7)^2=(3b+1-(b-7))•(3b+1+(b-7))=(3b+1-b+7)•(3b+1+b-7)=(2b+8)•(4b-6)=2(b+4)•2(2b-3)=2•2(b+4)•(2b-3)=4(b+4)•(2b-3)