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DashaZhovnirenko
@DashaZhovnirenko
August 2022
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СРОЧНО!!!!!
Нагревательный элемент сопротивлением 100 Ом выделил 12 МДж теплоты за 20 мин. Какова сила тока в цепи?
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arcticnet
Q = I
2
Rt.=12МДж =12*10 в 6 степени.
I2 = Q\Rt I = корень квадратный из Q\Rt
12*10 в 6 степени\100*1200 = 1200 А.
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Answers & Comments
I2 = Q\Rt I = корень квадратный из Q\Rt
12*10 в 6 степени\100*1200 = 1200 А.