2) AB = √((xB-xA)²+(yB-yA)²+(zB-zA)²) = 1 4 4 9 = 3.
BC = √((xC-xB)²+(yC-yB)²+(zC-zB)²) = 9 0 9 18 = 3√2 ≈ 4,242640687.
AC = √((xC-xA)²+(yC-yA)²+(zCB-zA)²) = 4 4 1 9 = 3.
3) Ответ во вложении.
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2) AB = √((xB-xA)²+(yB-yA)²+(zB-zA)²) = 1 4 4 9 = 3.
BC = √((xC-xB)²+(yC-yB)²+(zC-zB)²) = 9 0 9 18 = 3√2 ≈ 4,242640687.
AC = √((xC-xA)²+(yC-yA)²+(zCB-zA)²) = 4 4 1 9 = 3.
3) Ответ во вложении.