7.32
y'=[sinx(3sinx-2)-cosx*(-3cosx)]/(2-3sinx)^2=
=[3sin^2x-2sinx+3cos^2x]/(2-3sinx)^2=
=(3-2sinx)/(2-3sinx)^2
7.35
1/2(2-3x^4)^(-1/2)*(-12x^3)=6x^3/sqrt(2-3x^4)
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Verified answer
7.32
y'=[sinx(3sinx-2)-cosx*(-3cosx)]/(2-3sinx)^2=
=[3sin^2x-2sinx+3cos^2x]/(2-3sinx)^2=
=(3-2sinx)/(2-3sinx)^2
7.35
1/2(2-3x^4)^(-1/2)*(-12x^3)=6x^3/sqrt(2-3x^4)