Ответ:
sinacosa ÷ ctaga - 1
(1+1) = 2 tga÷ ctga+2
(1+1)=2 tga÷ctga-2
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Ответ:
sinacosa ÷ ctaga - 1
(1+1) = 2 tga÷ ctga+2
(1+1)=2 tga÷ctga-2