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DashaNottet
@DashaNottet
August 2022
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Айнура55
Y^4:y*(y^2)^3=y^4-1+6=y^9
5x^2y-8x^2y+x^2y=-2x^2y
(2ab^2)^4*(2a^2b)^3=16a^4b^8*8a^6b^3=
128a^10b^11
(m^4)^7/(m^3)^9*m=m^28/m^28=1
(2^5)^2*3^10/6^7=2^10*3^10/2^7*3^7=
2^3*3^3=8*27=216
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Answers & Comments
5x^2y-8x^2y+x^2y=-2x^2y
(2ab^2)^4*(2a^2b)^3=16a^4b^8*8a^6b^3=
128a^10b^11
(m^4)^7/(m^3)^9*m=m^28/m^28=1
(2^5)^2*3^10/6^7=2^10*3^10/2^7*3^7=
2^3*3^3=8*27=216