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yasashagarbuz
@yasashagarbuz
October 2021
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oganesbagoyan
Verified answer
У = cos(4x-8).
у' = (cos(4x-8) )' = -sin(4x-8)*(4x -8)' = -4sin(4x-8) .
-------------
y = Ln²(tq(3+2x)) -4x .
y ' = ( Ln²(tq(3+2x)) -4x)' = ( Ln²(tq(3+2x)))' - (4x)' =
2Ln(tq(3+2x))*(tq(3+2x))' -4 = 2Ln(tq(3+2x))*(1/sin²(3+2x )*((3+2x)' -4 =
4(Ln(tq(3+2x))/sin²(3+2x) -1).
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Answers & Comments
Verified answer
У = cos(4x-8).у' = (cos(4x-8) )' = -sin(4x-8)*(4x -8)' = -4sin(4x-8) .
-------------
y = Ln²(tq(3+2x)) -4x .
y ' = ( Ln²(tq(3+2x)) -4x)' = ( Ln²(tq(3+2x)))' - (4x)' =
2Ln(tq(3+2x))*(tq(3+2x))' -4 = 2Ln(tq(3+2x))*(1/sin²(3+2x )*((3+2x)' -4 =
4(Ln(tq(3+2x))/sin²(3+2x) -1).