Ответ:
1)Ar(N2O5)=14*2+16*5=108
Ar(SiCI4)=28+35*4=168
Ar(H2SiO3)=1*2+28+16*3=78
Ar(C6H12O6)=12*6+1*12+16*6=180
Ar(Ba(OH)2=137*16+1*2=2 194
2) 16*6=96
3) 16*4=64
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Ответ:
1)Ar(N2O5)=14*2+16*5=108
Ar(SiCI4)=28+35*4=168
Ar(H2SiO3)=1*2+28+16*3=78
Ar(C6H12O6)=12*6+1*12+16*6=180
Ar(Ba(OH)2=137*16+1*2=2 194
2) 16*6=96
3) 16*4=64