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prostttt
@prostttt
October 2021
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Срочно. Полное решение.
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tolya91
МО1=3=PR
RO2=PO2-PR=5
O1O2=8+3=11
по теореме Пифагора
О1R^2=O1O2^2-RO2^2
O1R=4sqrt{6}=MP
S(O1MPO2)=S(MPRO1)+S(O1RO2)
S(MPRO1)=MP*PR=12sqrt{6}
S(O1RO2)=(1/2)*O1R*RO2=10sqrt{6}
S(O1MPO2)=22sqrt{6}
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Thanks 1
prostttt
что значит sqrt ?:D
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Answers & Comments
RO2=PO2-PR=5
O1O2=8+3=11
по теореме Пифагора
О1R^2=O1O2^2-RO2^2
O1R=4sqrt{6}=MP
S(O1MPO2)=S(MPRO1)+S(O1RO2)
S(MPRO1)=MP*PR=12sqrt{6}
S(O1RO2)=(1/2)*O1R*RO2=10sqrt{6}
S(O1MPO2)=22sqrt{6}