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ENZHE62
@ENZHE62
September 2021
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Срочно! Помогите!
5(2-х)-(х+3) ≤ 4(х-6)
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Vicus44ea
10-5x-x-3 ≤ 4x-24
-5x-x-4x ≤ -24-10+3
-10x ≤ -31
x ≥ 31/10
x ≥ 3,1
x принадлежит интервалу [3,1 ; +∞)
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Answers & Comments
-5x-x-4x ≤ -24-10+3
-10x ≤ -31
x ≥ 31/10
x ≥ 3,1
x принадлежит интервалу [3,1 ; +∞)