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July 2022
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срочно помогите 5*5^2х-5^х-4>0
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Mariia56
А вот и я.
5*5^x-5^x-4>0
Пусть 5^x-t
5t²-t-4>0
5t²-t-4=0
D=1+81=81
√81=9
t1=1+9/2=5
t2=1-9/2=-4 посторонний корень
5^x>5
x>1
Ответ(1;+∞)
1 votes
Thanks 1
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Answers & Comments
5*5^x-5^x-4>0
Пусть 5^x-t
5t²-t-4>0
5t²-t-4=0
D=1+81=81
√81=9
t1=1+9/2=5
t2=1-9/2=-4 посторонний корень
5^x>5
x>1
Ответ(1;+∞)