Ответ:
Объяснение:
1393) 238U92----->234U92 + 4He2+2(0e-1)
1 α и 2 β
=============================
1394) 237Np93------->213Bi83 + 6(4He2) + 2(0e-1)
6 α и 2 β
==============================
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Ответ:
Объяснение:
1393) 238U92----->234U92 + 4He2+2(0e-1)
1 α и 2 β
=============================
1394) 237Np93------->213Bi83 + 6(4He2) + 2(0e-1)
6 α и 2 β
==============================