φ=t+t²+t³ t=3 c a=350 м/с²
ω=dφ/dt=1+2*t+3*t²
R=ω²/a=(1+2*t+3*t²)²/a=(1+2*3+3*9)²/350=3.3 м
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h=2*σ/(ρ*g*r)=2*33*10^-3/(960*10*1.1)=6.25*10^-3 м (6,25 мм)
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T=273+131=404 K
v=√(3*R*T/M)=√(3*8.31*404/4*10^-3)=1587 м/с
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φ=t+t²+t³ t=3 c a=350 м/с²
ω=dφ/dt=1+2*t+3*t²
R=ω²/a=(1+2*t+3*t²)²/a=(1+2*3+3*9)²/350=3.3 м
==============
h=2*σ/(ρ*g*r)=2*33*10^-3/(960*10*1.1)=6.25*10^-3 м (6,25 мм)
=================
T=273+131=404 K
v=√(3*R*T/M)=√(3*8.31*404/4*10^-3)=1587 м/с
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