Ответ:
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Объяснение:
1a ∛... = 0,3*5 = 1,5
1б = 4*0,3 = 1,2
1в ∛./. = 5/10= 0,5
1г ... =
1д ∛./. = ∛(27/8) = 3/2 = 1,5
2а ∛2 * ∛500 = ∛1000 = 10
2б =
2в ∛54/∛2 = ∛(54/2) = ∛27 = 3
2г =
3а ∛5⁹ = 5³ = 125
3б = 0,3² = 0,09
3в = 0,3²*2³ = 0,09*8= 0,72
3г = 0,5²* 4³ = 2*2*4 = 16
4a = =
4б = ∛3
4в =
4г =
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Answers & Comments
Ответ:
.....................
Ответ:
Объяснение:
1a ∛... = 0,3*5 = 1,5
1б
= 4*0,3 = 1,2
1в ∛./. = 5/10= 0,5
1г ... =![\sqrt[4]{625} /\sqrt[4]{16} = 5/2 = 2,5 \sqrt[4]{625} /\sqrt[4]{16} = 5/2 = 2,5](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B625%7D%20%2F%5Csqrt%5B4%5D%7B16%7D%20%3D%205%2F2%20%3D%202%2C5)
1д ∛./. = ∛(27/8) = 3/2 = 1,5
2а ∛2 * ∛500 = ∛1000 = 10
2б
= ![\sqrt[4]{1296} =\sqrt{36} = 6 \sqrt[4]{1296} =\sqrt{36} = 6](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B1296%7D%20%3D%5Csqrt%7B36%7D%20%3D%206)
2в ∛54/∛2 = ∛(54/2) = ∛27 = 3
2г
= ![\sqrt[4]{16} =2 \sqrt[4]{16} =2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D2)
3а ∛5⁹ = 5³ = 125
3б = 0,3² = 0,09
3в = 0,3²*2³ = 0,09*8= 0,72
3г = 0,5²* 4³ = 2*2*4 = 16
4a =
= ![\sqrt[12]{5} \sqrt[12]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B5%7D)
4б = ∛3
4в =![\sqrt[4]{2} \sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
4г =![\sqrt[6]{5} \sqrt[6]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B5%7D)