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Elisabeth1111
@Elisabeth1111
March 2022
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Срочно, помогите, пожалуйста
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lkulikova51
Пусть AC/2=AO=x, BD/2=BO=y, тогда по теореме Пифагора
x^2+y^2=25^2
AC-BD=2x-2y=10; x-y=5; x=y+5
(y+5)^2+y^2=625; 2y^2+10y-600=0;
y^2+5y-300=0; y1=-20; y2=15 x2=20
AC=40; BD=30
S=(40*30)/2=600
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Elisabeth1111
Огромное спасибо))
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Answers & Comments
x^2+y^2=25^2
AC-BD=2x-2y=10; x-y=5; x=y+5
(y+5)^2+y^2=625; 2y^2+10y-600=0; y^2+5y-300=0; y1=-20; y2=15 x2=20
AC=40; BD=30
S=(40*30)/2=600