СРОЧНО! ПОМОГИТЕ ПОЖАЛУЙСТА. Created by NovellaKim127. algebra-ru

СРОЧНО! ПОМОГИТЕ ПОЖАЛУЙСТА...

NovellaKim127 @NovellaKim127

August 2022 1 29 Report

СРОЧНО! ПОМОГИТЕ ПОЖАЛУЙСТА

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$\displaystyle\bf\\1)\\\\2^{\log_{2}5 } =5\\\\2)\\\\\log_{3} 3=1\\\\3)\\\\\log_{7} 1=0\\\\4)\\\\\log_{12} 4+\log_{12} 36=\log_{12} (4\cdot36)=\log_{12} 144=\log_{12} 12^{2} =\\\\=2\cdot\underbrace{\log_{12} 12}_{1}=2\cdot 1=2\\\\5)\\\\\log_{2} 11-\log_{2} 44=\log_{2} \frac{11}{44} =\log_{2} \frac{1}{4}=\log_{2} 2^{-2} =\\\\=-2\cdot\underbrace{\log_{2} 2}_{1}=-2\cdot 1=-2$

При решении были использованы формулы :

$\displaystyle\bf\\\log_{a} a=1\\\\\log_{a}1=0\\\\a^{\log_{a} b}=b\\\\\log_{a} x+\log_{a} y=\log_{a} (x\cdot y)\\\\\log_{a} x-\log_{a} y=\log_{a} (\frac{x}{y} )$

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