(1)
(2х-5)/3=7 |×3
2х-5=21
2х=26
х=13
(2)
12/17-3а=6
6(17-3а)=12 |÷6
17-3а=2
3а=15
а=5
(3)
(5х+1)/9=9
(5х+1)/9=95х+1=81
(5х+1)/9=95х+1=815х=80
х=16
(4)
87/(6х+5)=3
3(6х+5)=87 |÷3
6х+5=29
6х=24
х=4
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Answers & Comments
(1)
(2х-5)/3=7 |×3
2х-5=21
2х=26
х=13
(2)
12/17-3а=6
6(17-3а)=12 |÷6
17-3а=2
3а=15
а=5
(3)
(5х+1)/9=9
(5х+1)/9=95х+1=81
(5х+1)/9=95х+1=815х=80
х=16
(4)
87/(6х+5)=3
3(6х+5)=87 |÷3
6х+5=29
6х=24
х=4
a = 5
x = 16
a = 5
x = 16
x = 4