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danich21
@danich21
August 2022
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mikael2
1. y=√3sinx+cosπ/6+x²/π
y'=√3cosx+2x/π x0=π/3
y'(π/3)=√3/2+2/3
2. f(x)=x³+x f'(x)=3x²+1 f'(x0)=3+1=4
y= f'(x0)(x-x0)+ f(x0) f(x0)=1³+1=2
y=4(x-1)+2
y=4x-2
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Answers & Comments
y'=√3cosx+2x/π x0=π/3 y'(π/3)=√3/2+2/3
2. f(x)=x³+x f'(x)=3x²+1 f'(x0)=3+1=4
y= f'(x0)(x-x0)+ f(x0) f(x0)=1³+1=2
y=4(x-1)+2
y=4x-2