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patric01
@patric01
August 2022
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Срочно!! Помогите решить пример ( x^2-6x+8)\(x-1) +(x-4)\(x^2-3x+2)<=0
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nafanya2014
Verified answer
X²-6x+8=(x-2)(x-4)
x²-3x+2=(x-1)(x-2)
x²-4x+5>0 при любом х, так как D=(-4)²-20 <0
Применяем метод интервалов
_-__ (1) _+_(2) ___-___ [4] _+__
О т в е т. (-∞;1)U(2;4]
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Answers & Comments
Verified answer
X²-6x+8=(x-2)(x-4)x²-3x+2=(x-1)(x-2)
x²-4x+5>0 при любом х, так как D=(-4)²-20 <0
Применяем метод интервалов
_-__ (1) _+_(2) ___-___ [4] _+__
О т в е т. (-∞;1)U(2;4]